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Thermodynamics

Question
CBSEENCH11006166

Calculate the number of kJ of heat necessary to raise the temperature of 60.0g of aluminium from 35 to 55°C. Molar heat capacity of aluminium is 24 J mol–1 K–1.

Solution

We know, 
      straight q space equals space straight n space cross times space straight C space cross times space increment straight T                  ...(1)
 Here comma space space straight n space equals space 60 over 27 mol semicolon space space space straight C space equals space 24 space straight J space mol to the power of negative 1 end exponent straight K to the power of negative 1 end exponent semicolon
space space space increment straight T space equals space left parenthesis 55 minus 35 right parenthesis straight K space equals space 20 straight K
Substituting the values in eq. (1), we get
  straight q space equals space open parentheses 60 over 27 mol close parentheses space cross times space left parenthesis 24 space straight J space mol to the power of negative 1 end exponent straight K to the power of negative 1 end exponent right parenthesis space cross times space 20 straight K
                     = 1066.7 J = 1.07 kJ