Question
What becomes of the energy supplied to water molecules as they are heated in a closed container from 298K to 308K?
Solution
We know that,
∆H = ∆U + P ∆V
The water molecules are heated in a closed vessel, the volume of the vessel remains the same i.e.
V = 0 so that P∆V = 0 under these conditions.
Thus, the entire heat supplied by heating from 298K to 308K is used to increase the internal energy of water molecules.
∆H = ∆U + P ∆V
The water molecules are heated in a closed vessel, the volume of the vessel remains the same i.e.
V = 0 so that P∆V = 0 under these conditions.
Thus, the entire heat supplied by heating from 298K to 308K is used to increase the internal energy of water molecules.
