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Thermodynamics

Question
CBSEENCH11006148

Compute internal energy change of a system if it
(i) absorbs 500 kJ heat and does 300 kJ work.

(ii) loses 200 kJ heat and has 450 kJ of work done on it.

Solution

(i) Here,    q = 500 kJ,   w = -300 kJ
According to the first law of thermodynamics,
              increment straight U space equals space straight q space plus space straight w space equals space 500 space minus space 300 space equals space 200
(ii) Here,   q = -200 kJ,  w = 450 kJ
therefore space space space space increment straight U space equals space straight q space plus space straight w space equals space minus 200 space plus space 450 space equals space 250 space kJ