+91-8076753736[email protected]
logo
logo
-->

Thermodynamics

Question
CBSEENCH11006144
Wired Faculty App

If water vapour is assumed to be a perfect gas,
molar enthalpy change for vapourisation of 1 mol of water at 1bar and 100°C is 41kJ mol–1. Calculate the internal energy change, when

(i) 1 mol of water is vaporised at 1 bar pressure and 100°C.

Solution

straight i right parenthesis space The space change space straight H subscript 2 straight O space left parenthesis straight l right parenthesis space rightwards arrow straight H subscript 2 straight O left parenthesis straight g right parenthesis increment straight H equals space increment straight U space plus increment straight n subscript straight g RT or increment straight U equals space increment straight H space minus increment straight n subscript straight g RT substitutig space the space value comma space we space get increment straight U space equals 41.00 space KJ space mol to the power of negative 1 end exponent minus 1 space straight x 8.3 space straight J space mol to the power of negative 1 end exponent space straight K to the power of negative 1 end exponent space space space space space space space space space space space space straight x space 373 space straight K equals space 41.00 space kJ space mol to the power of negative 1 end exponent space minus 3.096 space kJ space mol to the power of negative 1 end exponent equals 37.904 space kJ space mol to the power of negative 1 end exponent

Some More Questions From Thermodynamics Chapter

Define an isolated system.

Define intensive properties.

Define extensive properties.

Why all living systems need to be 'open systems'?

Define state variables of a system.

From thermodynamic point of view, to which system the animals and plants belong?

What is a state function?

A thermodynamic state function is a quantity

What is reversible process in thermodynamics?

Define irreversible change.

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation