Question
In a process, 100J of heat energy is supplied and 50J of work is done on the system. What is the change in internal energy of the system ?
Solution
We have given,
heat = 100J
work= 50 J
change of internal energy is given by,
∆U = q + w
= 100 J + 50 J = 150J
heat = 100J
work= 50 J
change of internal energy is given by,
∆U = q + w
= 100 J + 50 J = 150J
