Comment on the thermodynamic stability of NO(g), given
$1 half straight N subscript 2 left parenthesis straight g right parenthesis space plus space 1 half straight O subscript 2 left parenthesis straight g right parenthesis space rightwards arrow space space NO left parenthesis straight g right parenthesis semicolon$ $increment subscript straight r straight H to the power of circled dash space equals space 90 space kJ space mol to the power of negative 1 end exponent$
$NO left parenthesis straight g right parenthesis space plus space 1 half straight O subscript 2 left parenthesis straight g right parenthesis space rightwards arrow space space NO subscript 2 left parenthesis straight g right parenthesis semicolon space increment subscript straight r straight H to the power of circled dash space equals space minus 74 space kJ space mol to the power of negative 1 end exponent$

Solution

Since in the first reaction, energy is absorbed, therefore NO(g) is unstable. But in the second reaction, energy is released, therefore NO₂(g) is stable. Hence, unstable NO (g) changes into stable NO₂(g).

Some More Questions From Thermodynamics Chapter

Why all living systems need to be 'open systems'?

Define state variables of a system.

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Thermodynamics

Some More Questions From Thermodynamics Chapter

Why all living systems need to be 'open systems'?

Define state variables of a system.

From thermodynamic point of view, to which system the animals and plants belong?

What is a state function?

A thermodynamic state function is a quantity

What is reversible process in thermodynamics?

Define irreversible change.

Name the variable that is kept constant in isochoric process and isobaric process.

Give one difference between an isothermal and an adiabatic process.

For the process to occur under adiabatic conditions, the correct condition is

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