A mixture of dihydrogen and dioxygen at one bar pressure contains 20% by weight of dihydrogen. Calculate the partial pressure of dihydrogen.

Solution

Lets space the space weight space of space dihyrogen space be space 20 space ga space nd space the space weight dioxygen space be space 80 straight g. Then comma space the space number space of space moles space of space dihydrogen comma space straight n subscript straight H subscript 2 end subscript 20 over 2 equals space 10 space moles space and space the space number space of space moles space of space dioxygen comma space straight n subscript straight O subscript 2 equals space end subscript fraction numerator 80 over denominator 32 space end fraction equals 2.5 moles Given comma space total space pressure space of space the space mixture comma space straight p subscript total equals 1 space bar then comma space partial space pressure space of space dihydrogen comma straight p subscript straight H subscript 2 end subscript equals space fraction numerator straight n subscript straight H subscript 2 end subscript over denominator straight n subscript straight H subscript 2 end subscript plus straight n subscript straight o subscript 2 end subscript end fraction space straight x space straight p subscript total equals fraction numerator 10 over denominator 10 plus 25 end fraction straight x space 1 equals 0.8 space bar

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