Question

Calculate the total pressure in a mixture of 8g of dioxygen and 4g of dihydrogen confined in a vessel of 1 dm³ at 27°C. R = 0·083 bar dm³ k^–1 mol^–1.

Name: Wired Faculty - The Best Learning App
Rating: 4.6 (1864 reviews)

Solution

Number of moles of dioxygen (n₁,)

equals space fraction numerator Mass space of space dioxygen over denominator Molecular space mass end fraction space equals space fraction numerator 8 straight g over denominator 32 space straight g space mol to the power of negative 1 end exponent end fraction space equals space 0.25 space mol

Number of moles of dihydrogen (n₂)

equals space fraction numerator Mass space of space dihydrogen over denominator Molecular space mass end fraction space equals space fraction numerator 4 straight g over denominator 2 straight g space mol to the power of negative 1 end exponent end fraction space equals space 2 space mol

Temperature (T) = 27+ 273 = 300 K
Now let us calculate the partial pressure of dioxygen and dihydrogen by using ideal gas equation,

space space space space straight P subscript straight O subscript 2 end subscript space equals space fraction numerator straight n subscript 1 RT over denominator straight V end fraction space equals space fraction numerator left parenthesis 0.24 space mol right parenthesis space cross times left parenthesis 0.083 space bar space dm cubed space straight K to the power of negative 1 end exponent space mol to the power of negative 1 end exponent right parenthesis space cross times space 300 space straight K over denominator 1 space dm cubed end fraction space space space equals 6.225 space bar straight P subscript straight H subscript 2 end subscript space equals space fraction numerator straight n subscript 2 RT over denominator straight V end fraction equals space fraction numerator left parenthesis 2 space mol right parenthesis space cross times space left parenthesis 0.083 space bar space dm cubed thin space straight K to the power of negative 1 end exponent space mol to the power of negative 1 end exponent right parenthesis space cross times space 300 straight K over denominator 1 space dm cubed end fraction space space space space space space equals space 49.8 space bar therefore space space space Total space pressure space of space gaseous space mixtu equals space 6.225 space space bar space plus space 49.8 space bar space equals space 56.025 space bar space space space space space space space space space space space space space space space space space

For Daily Free Study Material Join wiredfaculty