300 mL of a gas A at a pressure of 600 mm is mixed with 200mL of another gas B at a pressure of 700 mm in a vessel of 2-litre capacity. What will be the total pressure of the resulting mixture, if the temperature is kept constant?
Let the partial pressure of the gases A and B be represented by PA and PBrespectively.
(i) Partial pressure of gas A in 2 litre flask:
V1 = 300 mL; P2 = 600 mm
V2 = 2 L = 2 x 1000 = 2000 mL; PA = ?
According to Boyle's law, P1V1 = P2V2
i.e. 600 x 300 = PA x 2000
(ii) Partial pressure of gas B in 2 litre flask:
V1 = 200 mL, P1 = 700 mL
V2 = 2 litre = 2 x 1000 = 2000 mL
PB = ?
According to Boyle's law,
P1V1 = P2V2
i.e. 700 x 200 = PB X 2000
Total pressure exerted by the mixture
