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States Of Matter

Question
CBSEENCH11005927
Wired Faculty App

Calculate the temperature of 4·0 moles of a gas occupying 5 dm3 at 3·32 bar (R = 0·083 bar dm3 K–1 mol–1).

Solution

Here,
n = 4.0 mol
P = 3.32 bar
V = 5 dm3,  
R = 0.083 bar dm3 K-1 mol-1

Applying ideal gas equation PV = nRT,
or space space space space straight T space equals space PV over nR
Substituting the values, we have,
 straight T space equals space fraction numerator 3.32 space bar space cross times space 5 space dm cubed over denominator 4 space mol space cross times space 0.083 space bar space dm cubed space straight K to the power of negative 1 end exponent space mol to the power of negative 1 end exponent end fraction space space space space equals space 50 space straight K         

Some More Questions From States of Matter Chapter

How pressure of a given sample of gas is related to absolute temperature at constant volume?

How is the pressure of a gas related to the number of molecules of the gas at constant temperature and volume?

What is standard (or normal) temperature and pressure (STP)?

What does SATP stand for? Define it.

What is the value of molar volume at STP?

What is standard molar volume?

What is the value of gas constant in SI units?

What is meant by aqueous tension?

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