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States Of Matter

Question
CBSEENCH11005924

The drain cleaner, Drainex contains small bits of aluminium which react with caustic soda to produce dihydrogen. What volume of dihydrogen at 20°C and one bar will be released when 0·15g of aluminium reacts?

Solution

Al reacts with caustic soda to produce dihydrogen.
stack 2 Al with 2 cross times 27 straight g below space plus 2 NaOH plus 2 straight H subscript 2 straight O rightwards arrow space 2 NaAlO subscript 2 space plus space stack 3 straight H subscript 2 with 3 cross times 22400 space mL space at space STP below
 
54g Al on reacting with caustic soda produces
                                                equals space 3 space cross times space 22400 space mL space straight H subscript 2
therefore space space 0.15 space straight g space Al space on space reacting space with space caustic space soda space would space produce space
space space equals space fraction numerator 3 space cross times space 22400 over denominator 54 end fraction cross times 0.15 space mL space straight H subscript 2 space equals space 186.7 space mL
Applying the gas equation
        left parenthesis STP space condition right parenthesis space fraction numerator straight P subscript 1 straight V subscript 1 over denominator straight T subscript 1 end fraction space equals space fraction numerator straight P subscript 2 straight V subscript 2 over denominator straight T subscript 2 end fraction space left parenthesis Reqd. space condition right parenthesis
space space space space space fraction numerator 1 space atm space cross times space 186.7 space mL over denominator 273 straight K end fraction space equals space fraction numerator 0.987 space atm space cross times space straight V subscript 2 over denominator 293 space straight K end fraction
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open square brackets because space 1 space bar space equals space 0.987 space atm close square brackets
space space space therefore space space space straight V subscript 2 space equals space fraction numerator 1 space cross times space 186.7 over denominator 273 end fraction cross times fraction numerator 293 over denominator 0.987 end fraction space equals space 203.0 space mL