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States Of Matter

Question
CBSEENCH11005918

Write the units of the gas constant R in different scales of measurement ?

Solution

The units of the gas constant (or numerical value) R in different scales of measurement may be calculated as follows:

1. In SI units:
One mole of a gas under standard conditions of temperature and pressure (STP or NTP) occupies a volume of 22·7L.
therefore space space space Pressure space left parenthesis straight P right parenthesis space equals space 1 space bar space equals space 10 to the power of 5 Pa
Temperature space left parenthesis straight T right parenthesis space equals space 273.15 space straight K
Volume space left parenthesis straight V right parenthesis space equals space 22.7 space straight L space space equals space 22.7 space cross times space 10 to the power of negative 3 end exponent straight m cubed
According space to space ideal space gas space equation comma
space space space space space space space space space PV space equals space nRT
or space space space space space space space straight R space equals space PV over nT
or space space space space space space space space straight R space equals space fraction numerator 10 to the power of 5 Pa space cross times space 22.7 space cross times space 10 to the power of negative 3 end exponent straight m cubed over denominator 1 space mol space cross times space 273.15 space straight K end fraction
space space space space space
           space equals space fraction numerator 10 to the power of 5 Nm to the power of negative 2 end exponent space cross times space 22.7 space cross times space 10 cubed straight m cubed over denominator 1 space mol space cross times space 273.15 space straight K end fraction
space equals space 8.314 space Nm space mol to the power of negative 1 end exponent straight K to the power of negative 1 end exponent
space equals space 8.314 space straight J space mol to the power of negative 1 end exponent straight K to the power of negative 1 end exponent left parenthesis 1 space NM space equals space 1 straight J right parenthesis

2. Under NTP condition (for one mole of the gas):One mole of any gas at 0°C (i.e. 273·15K.) and under 1 bar pressure occupies 22.7 L
    therefore space space space space Pressure space left parenthesis straight P right parenthesis space equals space 1.0 space bar
space Temperature space left parenthesis straight T right parenthesis space equals space space 273.15 space straight K
Volume space left parenthesis straight V right parenthesis space equals space 22.7 space dm cubed
space space space space space space space space space space space space straight n space equals space 1 space mol
According to ideal gas equation,
                    PV = nRT
or space space space space space space space space space straight R space equals space PV over nT
Substituting the values, we have,
               straight R space equals space fraction numerator left parenthesis 1.0 space bar right parenthesis space cross times space left parenthesis 22.7 space dm cubed right parenthesis over denominator left parenthesis 1 space mol right parenthesis space cross times space left parenthesis 273.15 space straight K right parenthesis end fraction
space space space space equals 0.083 space bar space dm cubed space straight K to the power of negative 1 end exponent space mol to the power of negative 1 end exponent