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States Of Matter

Question
CBSEENCH11005916

Calculate the total number of electrons present in 1.4 g of dinitrogen gas.

Solution
Number space of space moles space space equals space fraction numerator Weight space over denominator Molecular space mass end fraction
therefore space space 1.4 space straight g space straight N subscript 2 space equals space fraction numerator 1.4 over denominator 28 end fraction space mol space equals space 0.05 space mol
space space space space space space space space space space space space space space space space space space equals space 0.05 space cross times space 6.022 space cross times space 10 to the power of 23 space molecule
space space space space space space space space space space space space space space space space space space space equals 3.01 space cross times space 10 to the power of 22 space molecules
Now space 1 space molecule space of space straight N subscript 2 space contains space space equals space 14 space electrons
space space space space space space space space therefore space space Total space number space of space electrons space present space in space 1.4 space straight g space straight N subscript 2
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 3.01 space cross times space 10 to the power of 22 space cross times space 14
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 4.214 space cross times 10 to the power of 23 space electrons