Using bond order show that N₂ would be expected to have a triple bond, F₂ a single bond and Ne₂ no bond.

Solution

We know that bond order represents a number of covalent bonds in a molecule or a species. Bond order =

1 half left square bracket straight N subscript straight b space minus space straight N subscript straight a right square bracket

left parenthesis straight i right parenthesis space Bond space order space of space straight N subscript 2 space equals space 1 half left square bracket 8 minus 2 right square bracket space equals space 1 half cross times 6 space equals space 3 Thus space straight N subscript 2 space consists space of space straight a space triple space bond. left parenthesis ii right parenthesis space Bond space order space of space space space space space space space space space space space space space space space space space space space straight F subscript 2 space equals space 1 half left square bracket 8 minus 6 right square bracket space equals space 1 half cross times 2 space equals space 1

Thus F₂ consists of a single bond.
(iii) Bond order of Ne₂

equals 1 half left square bracket 8 minus 8 right square bracket space equals space 0

Thus Ne₂ consists of no bonds.

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