Question
Discuss the relatives stabilities, bond dissociation energies and bond lengths of O2, 
species.
Solution
For O2 molecule:
Nb = 8, Na = 4
As bond dissociation energies are directly proportional to the bond order, therefore, the dissociation energies of these molecular species are in order:
As greater the bond dissociation energy, greater is the stability; the stability of these species is also as in the above order.
As bond length is inversely proportional to bond order, therefore their bond lengths will be in order:
