Describe the change in hybridization (if any) of the Al atom in the following reaction:

13Al (Excited state) = ls22s-22p63s13px1 3py1 .Hence in AlCl3, Al undergoes sp2 hybridization to give it planar triangular structure. In AlCl4 , the empty 3p. orbital is also involved so that hybridization is sp3 and its shape is tetrahedral.