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Chemical Bonding And Molecular Structure

Question
CBSEENCH11005708

Using the orbital overlap concept, explain the formation of:
(i) O2 molecule            (ii) N2 molecule.

Solution
 (i) O2 molecule: The electronic configuration of oxygen atom
(z = 8) is 1 straight s squared space 2 straight s squared space 2 straight p subscript straight x superscript 2 space 2 straight p subscript straight y superscript 1 space 2 straight p subscript straight z superscript 1.
It has two half filled 2p-orbitals in its valence shell. In the formation of the oxygen molecule. One of the two half filled 2p-orbitals of each oxygen atom overlaps mutually along the internuclear axis to form σ bond. The other half-filled 2p orbitals of each oxygen atom undergo sidewise overlapping to form straight pi-bond.
Thus, two oxygen atoms are linked together by a double bond, one of which is sigma bond and other is straight pi a bond. 

(ii) N2 molecule. The electronic configuration of nitrogen atom (Z = 7) is
1 straight s squared 2 straight s squared 2 straight p subscript straight x superscript 1 2 straight p subscript straight y superscript 1 2 straight p subscript straight z superscript 1. It has three half filled 2p-orbitals in its valence shell. In the formation of the nitrogen molecule, one of the three half-filled 2p orbitals of each nitrogen atom overlaps mutually along the internuclear axis to form a bond. The other two 2p-half filled orbitals of a nitrogen atom undergo sidewise overlapping with their parallel oriented 2p-orbitals of other nitrogen to form two straight pi bonds. Thus, two nitrogen atoms are linked together by a triple bond, one of which is sigma bond and the other two are straight pi bonds.