-->

Chemical Bonding And Molecular Structure

Question
CBSEENCH11005687

Write the Lewis structure of nitrite space space NO subscript 2 superscript minus

Solution
Step I. Total number of valence electrons of NO2 = 5 + 6 + 6+1=18.

Step II.  Total number of electrons to be distributed in space space NO subscript 2 superscript minus space equals space 17 plus 1 space equals space 18
Step III. The skeletal structure of space NO subscript 2 superscript minus is O N O step.
Step IV. Putting one shared electron pair between the nitrogen and each of the oxygen atoms completing the octet of oxygen atoms.