+91-8076753736[email protected]
logo
logo
-->

Classification Of Elements And Periodicity In Properties

Question
CBSEENCH11005513
Wired Faculty App

Energy of an electron in the ground state of the hydrogen atom is -2.18 X 10-18J. Calculate the ionization enthalpy of atomic hydrogen in terms of J mol-1.

Solution

The enthalpy required removing an electron in the ground state of hydrogen atom
= - (its energy in the ground state)
= -(-2.18 x 10-18 J)
= 2.18 x 10-18 J
∴ Ionization enthalpy per mole of hydrogen atoms
equals space 2.18 space cross times space 10 to the power of negative 18 end exponent space cross times space 6.022 space cross times space 10 to the power of 23 kJ equals space 13.127 space straight x 10 to the power of 5 space straight J space mol to the power of negative 1 end exponent

Some More Questions From Classification of Elements and Periodicity in Properties Chapter

What is valency of an element?

Gallium was named by Mendeleev as

What are magic numbers?

Which property is the basis of long form of periodic table?

How many elements are placed in each period of the p-block?

What is the number of groups in: (i) p-block  (ii) d-block?

How many elements are present in:
(i) second period    
(ii) fourth period    
(iii) sixth period?

What is the name given to the s-block elements?

To which block the element with outer electronic configuration 4s23d10 belongs?

Why are there 10 elements in each series of d-block?

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation