Question
With the help of ground state electronic configuration of element Cr(Z= 24), deduce the possible values of four quantum numbers for the 19th electron of Cr.
Solution
The ground state electronic configuration of Cr is
[Ar] 4s1 3d5 or 1s2 2s2 2p6 3s2 3p6 4s1 3d5
The 19th electron is 4s1
∴ For 4s1 electron
n = 4, l = 0, m = 0, s = +1/2 or -1/2.
[Ar] 4s1 3d5 or 1s2 2s2 2p6 3s2 3p6 4s1 3d5
The 19th electron is 4s1
∴ For 4s1 electron
n = 4, l = 0, m = 0, s = +1/2 or -1/2.
