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Structure Of Atom

Question
CBSEENCH11005232
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Find: (a) the total number and (b) the total mass of neutrons in 7 mg of 14C. (Assume that mass of a neutron = 1.675 X 10-27 kg).

Solution

(a)  1 g atom of carbon = 14g
                               = 6.022 x 1023 atoms
   Each carbon atom open parentheses straight C presuperscript 14 close parentheses space has space 14 minus 6 space space equals space 8 space neutrons
     therefore space space space 6.022 space cross times space 10 to the power of 23 space atom space would space have space equals space 8 space cross times space 6.022 space cross times space 10 to the power of 23 space neutron therefore space space space space 14 straight g space or space 14000 space mg space have space space space space space space space space space space space space space space space space space space space space space space equals 8 space cross times 6.022 space cross times space 10 to the power of 23 space neutrons therefore space space space 7 mg space will space have space equals space fraction numerator 8 cross times 6.022 space cross times space 10 to the power of 23 over denominator 14000 end fraction cross times 7 space neutrons space equals space 2.4088 space cross times space 10 to the power of 21 space neutrons

(b) Mass of 1 neutron = 1.675 x 10-27 kg
therefore    Mass of 2.4088 x 1021 neutrons
      = (1.675 x 10-27kg) x (2.4088 x 1021)
      = 4.0347 x 10-6kg

Some More Questions From Structure of Atom Chapter

What is a proton?

Who discovered neutron?

What is a neutron?

What is the name of the remaining part of atom except outer orbit?

Name the particles which determine the mass of an element.

What are α-particles?

Why were neutrons discovered very late?

What are the fundamental particles present in a neutral atom having atomic number greater than 1?

Do protons and neutrons have identical mass?

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