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Structure Of Atom

Question
CBSEENCH11005228
Wired Faculty App

The diameter of zinc atom is 2.6 Å. Calculate: (a) radius of zinc atom in pm and (b) number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise.

Solution
(a) Diameter of zinc atom = 2.6 Å
                     equals space 2.6 space cross times space 10 to the power of negative 10 end exponent straight m equals 260 space cross times space 10 to the power of negative 12 end exponent straight m space equals 260 space pm   
therefore space space Radius space equals fraction numerator 260 space pm over denominator 2 end fraction space equals space 130 space pm
(b) Here, length = 1.6 cm = 1.6 x 10-2 m  
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Hence, number of atoms present along the length
                    equals space fraction numerator 1.6 space cross times space 10 to the power of negative 2 end exponent over denominator 2.6 space cross times space 10 to the power of negative 10 end exponent end fraction space equals space 6.154 space cross times space 10 to the power of 7                         

Some More Questions From Structure of Atom Chapter

Why were neutrons discovered very late?

What are the fundamental particles present in a neutral atom having atomic number greater than 1?

Do protons and neutrons have identical mass?

When α-particles are sent through a thin metal foil, most of them go straight through the foil. What inference do you draw from it?

What did Rutherford's experiment on scattering of particles show for the first time?

What is Plum-Pudding model of the atom?

Are neutrons present in all atoms?

Why are electrons called planetary electrons?

What are nucleons?

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