+91-8076753736 support@wiredfaculty.com
logo
logo

Sponsor Area

Structure Of Atom

Question
CBSEENCH11005226
Wired Faculty App

If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms which can be placed side by side in a straight line across length of scale of length 20 cm long.

Solution

Diameter of carbon atom  = 0.15 nm
   space space equals space 0.15 space cross times space 10 to the power of negative 9 end exponent straight m space equals space 1.5 space cross times space 10 to the power of negative 10 end exponent straight m
Length along which carbon atoms are to be placed
                            = 20 cm
                          space space space equals space 20 space cross times space 10 to the power of negative 2 end exponent straight m space equals space 2 space cross times space 10 to the power of negative 1 end exponent straight m
Hence, number of carbon atoms which can be placed along the length
                                 space space equals space fraction numerator 2 space cross times space 10 to the power of negative 1 end exponent straight m over denominator 1.5 space cross times space 10 to the power of negative 10 end exponent straight m end fraction space equals space 1.33 space cross times space 10 to the power of 9

Some More Questions From Structure of Atom Chapter

Name the particles which determine the mass of an element.

What are α-particles?

Why were neutrons discovered very late?

What are the fundamental particles present in a neutral atom having atomic number greater than 1?

Do protons and neutrons have identical mass?

When α-particles are sent through a thin metal foil, most of them go straight through the foil. What inference do you draw from it?

What did Rutherford's experiment on scattering of particles show for the first time?

What is Plum-Pudding model of the atom?

Are neutrons present in all atoms?

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation