Question
An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1 % more neutrons than the electrons, find the symbol of the ion.
Solution
Since the ion carries one unit negative charge, it means that in the ion, the number of electrons is one more than the number of protons. Let the number of electrons in the tube =x
No. of neutrons =
Number of electrons in the neutral atom = x - 1
Number of protons = x -1
Mass No. = No. of neutrons + No. of protons
37 = 1.111x + x - 1
or 38 = 2.111x
Symbol of the ion is 
-.
No. of neutrons =
Number of electrons in the neutral atom = x - 1
Number of protons = x -1Mass No. = No. of neutrons + No. of protons
37 = 1.111x + x - 1
or 38 = 2.111x
Symbol of the ion is -.
