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Structure Of Atom

Question
CBSEENCH11005262

Nitrogen laser produces a radiation at a wavelength of 337.1 nm. If the number of photons emitted is 5.6 x 1024, calculate the power of this laser. 

Solution

Energy of one photon of light (E) = hv
Energy of n photon of light  (En) = nhv
                                 equals space straight n hc over straight lambda           ...(1)
Here,  n = 5.6 x 1024;   h = 6.626 x 10-34 Js;
      straight v space equals 3.0 space cross times space 10 to the power of 8 ms to the power of negative 1 end exponent comma
straight lambda space equals space 337.1 space nm space equals space 337.1 space cross times space 10 to the power of negative 9 end exponent straight m
Substituting the values in eq. (1), we have
   straight E space equals space fraction numerator left parenthesis 5.6 space cross times 10 to the power of 24 right parenthesis thin space left parenthesis 6.626 space cross times space 10 to the power of negative 34 end exponent Js right parenthesis space left parenthesis 3.0 space cross times space 10 to the power of 8 space ms to the power of negative 1 end exponent right parenthesis over denominator 337.1 space cross times space 10 to the power of negative 9 end exponent straight m end fraction
space equals space 3.3 space cross times space 10 to the power of 6 space straight J