+91-8076753736 support@wiredfaculty.com
logo
logo

NCERT Classes

  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12

Previous-Year-Papers

  • CBSE Class 10 and 12
  • NEET Class 12
  • IIT JEE-Main Class 12
  • ICSE Class 10 Class 12
  • CLAT Class 12

Entrance Exams

  • IIT-JEE
  • NEET
  • CLAT
  • SSC-CGL
  • SSC-CHSL

State Boards

  • Assam Board
  • UP Board English Medium
  • Up Board Hindi Medium
  • CBSC Board English Medium
  • CBSC Board Hindi Medium
  • Manipur Board
  • Goa Board
  • Gujrat Board
  • Haryana Board English Medium
  • Haryana Board Hindi Medium
  • Uttarakhand Board English Medium
  • Uttarakhand Board Hindi Medium
  • Himachal Board English Medium
  • Himachal Board Hindi Medium
  • ICSE Board
  • Jharkhand Board English Medium
  • Jharkhand Board Hindi Medium
  • Karnataka Board
  • Meghalya Board
  • Nagaland Board
  • Punjab Board
  • Rajasthan Board English Medium
  • Rajasthan Board Hindi Medium

For Daily Free Study Material Join wiredfaculty

Home > Structure Of Atom

Sponsor Area

Structure Of Atom

Question
CBSEENCH11005258
Wired Faculty App

Calcualte the energy of one mole of photons of radiation whose frequency is 5 x 1014Hz.

Solution
Short Answer

Energy (E) of one photon = hv
Here,    h = 6.626 x  10-34 Js
            v = 5 x 1014 s-1
therefore space space straight E space equals space left parenthesis 6.626 space cross times space 10 to the power of negative 34 end exponent Js right parenthesis cross times left parenthesis 5 cross times 10 to the power of 14 straight s to the power of negative 1 end exponent right parenthesis
space space space equals space 3.313 space cross times 10 to the power of negative 19 end exponent straight J
therefore space space Energy space of space one space mole space of space photons
space space space space space space equals space left parenthesis 3.313 space cross times space 10 to the power of negative 19 end exponent straight J right parenthesis space cross times left parenthesis 6.022 space cross times space 10 to the power of 23 space mol to the power of negative 1 end exponent right parenthesis
space space space space space space space equals 199.51 space kJ space mol to the power of negative 1 end exponent


  • Bookmark
  • Facebook
  • WhatsApp
  • Twitter
  • Linkedin
  • Copy Link
  • twitter button
  • facebook logo
  • watsapp logo

Some More Questions From Structure of Atom Chapter

Why were neutrons discovered very late?

What are the fundamental particles present in a neutral atom having atomic number greater than 1?

Do protons and neutrons have identical mass?

When α-particles are sent through a thin metal foil, most of them go straight through the foil. What inference do you draw from it?

What did Rutherford's experiment on scattering of particles show for the first time?

What is Plum-Pudding model of the atom?

Are neutrons present in all atoms?

Why are electrons called planetary electrons?

What are nucleons?

Mock Test Series

Mock Test Series

  • NEET Mock Test Series
  • IIT-JEE Mock Test Series
  • CLAT Mock Test Series
  • SSC-CGL Mock Test Series
  • SSC-CHSL Mock Test Series

NCERT Sample Papers

  • CBSE English Medium
  • CBSE Hindi Medium
  • ICSE

Entrance Exams Preparation

  • NEET
  • IIT-JEE
  • CLAT
  • SSC-CGL
  • SSC-CHSL

ABOUT US

  • Company
  • Term of Use
  • Privacy Policy

NCERT SOLUTIONS

  • NCERT Solutions for Class-8th
  • NCERT Solutions for Class-9th
  • NCERT Solutions for Class-10th
  • NCERT Solutions for Class-11th
  • NCERT Solutions for Class-12th

CONTACT US

Phone Number

+91-8076753736

Email Address

support@wiredfaculty.com

Location

A2/44 Sector-3 Rohini Delhi 110085

Copyright © 2025 wiredfaculty. Powered by -wiredfaculty.com