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Structure Of Atom

Question
CBSEENCH11005240

The wavelength range of the visible spectrum extends from violet (400 nm) to red (750 nm). Express these wavelengths in frequencies (Hz). [1 nm = 10-9 m]

Solution

Frequency of violet light, 
   straight v space equals straight c over straight lambda space equals space fraction numerator 3.00 space cross times space 10 to the power of 8 ms to the power of negative 1 end exponent over denominator 400 space cross times space 10 to the power of negative 9 end exponent straight m end fraction space equals space 7.50 space cross times space 10 to the power of 14 Hz
Frequency of red light,
     straight v space equals straight c over straight lambda space equals space fraction numerator 3.00 space cross times space 10 to the power of 8 space ms to the power of negative 1 end exponent over denominator 400 space cross times space 10 to the power of negative 9 end exponent straight m end fraction
space space space space equals space 4.00 space cross times space 10 to the power of 14 Hz