-->

Some Basic Concepts Of Chemistry

Question
CBSEENCH11005107

The density of 3M solution of NaCl is 1.25g ml-1.  Calculate molality of the solution.

Solution
Here comma space straight M space equals 3 space mol space straight L to the power of negative 1 end exponent
therefore space space space Mass space of space NaCl space in space 1 straight L space solution space equals space 3 space straight x space 58.5 space equals space 175.5 space straight g
therefore space space space Mass space of space 1 space straight L space solution space equals space 1000 space cross times space 1.25 space equals space 1250 space straight g
space space space Mass space of space water space in space solution space equals space 1250 minus space 175.5 space equals space 1074.5 space straight g

therefore space space space space Molality space equals fraction numerator 3 space mol over denominator 1074.5 end fraction cross times 1000 space equals space 2.79 space straight m