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Some Basic Concepts Of Chemistry

Question
CBSEENCH11005104
Wired Faculty App

What is the concentration of sugar (C12H22O22) in mol L–1 if its 20g are dissolved in enough water to make a final volume up to 2L? 

Solution

Molar mass of sugar space open parentheses straight C subscript 12 straight H subscript 22 straight O subscript 11 close parentheses
                 space space equals space 12 cross times 12 plus 22 cross times 1 plus 11 cross times 16 space space equals 342 space straight g space mol to the power of negative 1 end exponent
Number of moles of sugar = space space fraction numerator 20 straight g over denominator 342 space straight g space mol to the power of negative 1 end exponent end fraction
                                      = 0.0585 mol
therefore  Molar concentration (molarity)
                       space space equals space fraction numerator Moles space of space solute over denominator Vol. space of space sol space in space straight L end fraction space equals fraction numerator 0.0585 over denominator 2 end fraction space space equals space 0.0293 space straight M

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