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Some Basic Concepts Of Chemistry

Question
CBSEENCH11005101
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A sample of NaNO3 weighing 0·38g is placed in a 50·0 mL volumetric flask. The flask is then filled with water to the mark on the neck. What is the molarity of the solution? 

Solution

Molar mass of NaNO3 = 85 g mol-1
therefore space space space space Number space of space moles space of space NaNO subscript 3 space equals space fraction numerator 0.38 over denominator 85 end fraction Litres space of space solution space equals space 50 over 1000 straight L space equals space 0.05 space straight L Molarity space equals space fraction numerator Moles space of space NaNO subscript 3 over denominator Litres space of space solution end fraction space space space space space space space space space space space space equals space fraction numerator 0.38 over denominator 85 end fraction cross times fraction numerator 1 over denominator 0.05 end fraction space equals space 0.089 space straight M

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