+91-8076753736 support@wiredfaculty.com
logo
logo

Sponsor Area

Some Basic Concepts Of Chemistry

Question
CBSEENCH11005100
Wired Faculty App

A solution is prepared by dissolving 5.3g of Na2CO3 in distilled water to give 500 mL of solution. Calculate the molarity of the solution.

Solution
Moles of Na2CO3
equals space fraction numerator Wt. space of space sodium space carbonate over denominator Molecular space mass space of space Na subscript 2 CO subscript 3 end fraction space equals space fraction numerator 5.3 over denominator 106 end fraction space space space space Volume space of space solution space equals space 500 space mL Molarity space equals space fraction numerator 5.3 over denominator 106 space cross times space 500 end fraction cross times 1000 space equals space 0.1 space straight M.

Some More Questions From Some Basic Concepts of Chemistry Chapter

Define the term significant figures.

What is the number of significant figures in 0.0026?

What is the number of significant figures in 9.984?

Express the Avogadro's number (6·023×1023) upto three significant figures.

What is the result of (5.472 - 1.12) to the appropriate number of signficant figures?

Express 0.0468 in scientific notation.

What does SI units stand for?

What is the relation between temperature in Kelvin (K) and temperature on centigrade scale?

The popular unit of pressure is atmosphere, how is it related to pascal?

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation