Question
Determine the empirical formula of an oxide of iron which has 69·9% iron and 30.1% dioxygen by mass.
Solution
|
Element |
Percentage |
Atomic Mass |
Atomic ration |
Simplest ratio |
Simplest whole number ratio |
|
Iron (Fe) |
69.9 |
55.85 |
69.9/55.85=1.25 |
1.25/1.25 =1 |
2 |
|
Oxygen (O) |
30.1 |
16.00 |
30.1/16.00=1.88 |
1.88/1.25=1.5 |
3 |
Empirical formula Fe2O3
