Calculate the atomic mass(average) of chlorine using the following data:

%Natural Abundance Molar mass
³⁵Cl 75·77 34·9689
³⁷Cl 24·23 36·9659

Solution

Fractional abundance of ³⁵Cl = 0·7577:
Molar mass = 34.9689
Fractional abundance of ³⁷Cl = 0.2423
Molar mass = 36.9659

therefore space space A v e r a g e space a t o m i c space m a s s equals space left parenthesis 0.7577 right parenthesis thin space left parenthesis 34.9689 space straight u right parenthesis space plus space left parenthesis 0.2423 right parenthesis thin space left parenthesis 36.9659 space straight u right parenthesis space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 26.4959 plus 8.9568 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 35.4527 space straight u space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space

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