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Some Basic Concepts Of Chemistry

Question
CBSEENCH11005011

Show that the law of reciprocal proportions is proved by the following results:
1·4g of the element A is known to combine with 1·6g of element B, while 0·5g of another element C combines with 3·5g of the element A and 2·857g of the element C combines with 22·857g of element B.

Solution

(i) In AB compound:
1.4 g of A combines with 1.6g of B
therefore 1 g of A combines with fraction numerator 1.6 over denominator 1.4 end fraction straight g space of space straight B space equals space 1.14 space straight g space of space straight B
(ii) For AC compound:
3.5 g of A combines with 0.5g of C
1g of A combines with fraction numerator 0.5 over denominator 3.5 end fraction straight g space of space straight C space equals 0.14 space straight g space of space straight C
Ratio of masses of B (in AB) and C(in AC) that combines with the fixed mass of A(1 g) is
fraction numerator Mass space of space straight B over denominator Mass space of space straight C end fraction space equals fraction numerator 1.14 over denominator 0.14 end fraction space equals space fraction numerator 8.14 over denominator 1 end fraction space space space space... left parenthesis 1 right parenthesis
(iii) In BC compound:
Ratio of masses of B and C, when they combine to form BC is
fraction numerator Mass space of space straight B over denominator Mass space of space straight C end fraction space equals space fraction numerator 22.857 over denominator 2.857 end fraction space equals space 8 over 1 space space space space space space... left parenthesis 2 right parenthesis
Since the two ratios (1) and (2) between the masses of B and C are same, hence the law of reciprocal proportion is proved.