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Some Basic Concepts Of Chemistry

Question
CBSEENCH11005099
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Calculate the normality of a solution containing 0.5 g NaOH in 250 mL of solution.

Solution

Gram equivalent is given as =
fraction numerator Given space molecular space mass space of space substance over denominator Molecular space mass space of space substance end fraction
Gram equivalent of NaOH = fraction numerator 0.5 over denominator 40 end fraction
Volume of solution = 250 mL
Normality is given as =
straight N space equals fraction numerator Gram space equivalent space over denominator volume space required end fraction straight x space 1000
therefore space space Normality space space equals space fraction numerator 0.50 over denominator 40 end fraction cross times 1 over 250 cross times 1000 space equals space 0.05 space straight N

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