Question
Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation:
(i) Calculate the mass of ammonia produced if 2·00 × 103 g dinitrogen reacts with 1·00×103 g of dihydrogen.
(ii) Will any of the two reactants remain un reacted?
(iii) If yes, which one and what would be its mass?
Solution
(i) 1 mol of N2 = 28g ; 3 mol of H2 = 6g; 28g of N2 react with 6g of H2
2000 of N2 would react with H2
Thus, N2 in the limiting reagent while H2 is the excess reagent
2 mol of N2 i.e. 28g of N2 produce NH3
= 2 mol = 2 x 17 = 34g
2000g of N2 would produce
NH3 =
(ii) H2 will remain unreacted.
(iii) Mass of H2 that remains unreacted = 1000 - 428.6 = 571.4 g.
2000 of N2 would react with H2Thus, N2 in the limiting reagent while H2 is the excess reagent
2 mol of N2 i.e. 28g of N2 produce NH3
= 2 mol = 2 x 17 = 34g
2000g of N2 would produceNH3 =
(ii) H2 will remain unreacted.
(iii) Mass of H2 that remains unreacted = 1000 - 428.6 = 571.4 g.
