Chlorine is prepared in the laboratory by treating manganese dioxide (MnO₂) with aqueous hydrochloric acid according to the reaction

$4 space HCl left parenthesis aq right parenthesis space plus space MnO subscript 2 left parenthesis straight s right parenthesis space rightwards arrow space 2 straight H subscript 2 straight O left parenthesis straight l right parenthesis space plus space MnCl subscript 2 left parenthesis aq right parenthesis space plus space Cl subscript 2 left parenthesis straight g right parenthesis$

How many grams of HCl react with 5.0 g of manganese dioxide?

Solution

1 mol [55+2 x16=87 g] MnO₂ reacts completely with 4 mol [4x 36.5=146g] of HCl

Therefore,

5.0 g of MnO₂ will react with

=(146/87) x5.0g of HCl

=8.4 g of HCl

Hence, 8.4g of HCl will react completely with 5.0g of manganese dioxide.

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