Question
How much potassium chlorate should be heated to produce 2.24 L of oxygen at NTP?
Solution
The balanced chemical equation is
2KClO3
2KCl + 3O2
2 moles 3 moles
2(39+35.5+48) 3 x 22.4 L
= 245 g (at NTP)
Stoichiometry indicates that
3 x 22.4L oxygen is produced from 245g KClO3
2.24 L oxygen is produced from 
2KClO3
2KCl + 3O22 moles 3 moles
2(39+35.5+48) 3 x 22.4 L
= 245 g (at NTP)
Stoichiometry indicates that
3 x 22.4L oxygen is produced from 245g KClO3
2.24 L oxygen is produced from 
