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Some Basic Concepts Of Chemistry

Question
CBSEENCH11005080

Calculate the quantity of lime required to soften 60000 litres of well water containing 16.2 g of calcium carbonate per hundred litre.

Solution
Balanced equation is
Ca(HCO3)2  + Ca(OH)2 rightwards arrow   2CaCO3 +2H2O
(40+2+24+96)     (40+32+2)
  = 162 g                     = 74 g
 16.2 g                            ?
(i) To calculate the weight of calcium bicarbonate present.
Weight of calcium bicarbonate present in 100 litres of well water = 16.2 g, Now 100 L well water contains
                          = 16.2 g Ca(HCO3)2
therefore 60000 L well water contains
                               equals space fraction numerator 16.2 over denominator 100 end fraction cross times 60000
equals space 9720 space straight g space Ca left parenthesis HCO subscript 3 right parenthesis subscript 2
(ii)  To calculate the quantity of lime required. Stoichiometry indicates that 162 g Ca(HCO3)requires 74 g Ca(OH)2
therefore space space space 9720 space straight g space Ca left parenthesis HCO subscript 3 right parenthesis subscript 2 space require
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 74 over 162 cross times 9820 space equals space 4440 space straight g space Ca left parenthesis OH right parenthesis subscript 2