Question
How many moles of oxygen can be obtained by the decomposition of 1 mole of potassium chlorate in the following reaction:
How many moles of reactants are needed for obtaining 1 mole of oxygen?
Solution
Balanced equation is,
2KClO3(s)
2KCl(s) + 3O2(g)
2 moles 3 moles
Stoichiometry indicates that:
2 moles KClO3 on decomposition give
= 3 moles of oxygen
1 mol KClO3 on decomposition would give
Again 3 moles of oxygen are produced from 2 moles of KClO3.
1 mol oxygen is produced form 
moles of KClO3 = 0.66 mol
2KClO3(s)
2KCl(s) + 3O2(g)2 moles 3 moles
Stoichiometry indicates that:
2 moles KClO3 on decomposition give
= 3 moles of oxygen
1 mol KClO3 on decomposition would giveAgain 3 moles of oxygen are produced from 2 moles of KClO3.
1 mol oxygen is produced form moles of KClO3 = 0.66 mol
