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Some Basic Concepts Of Chemistry

Question
CBSEENCH11005077

Calculate the amount of KClOneeded to supply sufficient oxygen for burning 112L CO gas at S.T.P.

Solution

The balanced chemical equations repersenting the reactions are:
             2 KClO subscript 3 space stack rightwards arrow space with increment on top space 2 KCl space plus 3 straight O subscript 2
              2CO + Orightwards arrow    2CO2
 
            2 moles
              (2 x 22.4L at STP)
Stoichiometry indicates that,
2 space moles space CO space identical to space 1 space mole space straight O subscript 2 space identical to space 2 divided by 3 space mole space KClO subscript 3
or   2 x 22.4 L  CO at S.T.P.
                    identical to 2 over 3 cross times left parenthesis 39 plus 35.5 plus 48 right parenthesis straight G
identical to 2 over 3 cross times 122.5 space straight g
therefore space space space 112 space straight L space CO space at space STP space identical to space 2 over 3 cross times fraction numerator 122.5 over denominator 2 space cross times space 22.4 end fraction cross times space 112
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 204.1666 space straight g space KClO subscript 3 space space space space space space space space space space space space space space space space space space space