Question
How many grams of barium sulphate are obtained when 26 g of barium chloride reacts with enough sulphuric acid? (Atomic mass of Ba = 137).
Solution
The balanced chemical equation representing the reaction is:
BaCl2 + H2SO4
BaSO4
+ 2HCl
1 mole 1 mole
137 + (2 x 35.5) 137 + 32 + (4 x 16)
208 g 233 g
26 g ?
Stoichiometry indicates that 208 g BaCl2 gives 233 g BaSO4
BaCl2 + H2SO4
BaSO4 + 2HCl1 mole 1 mole
137 + (2 x 35.5) 137 + 32 + (4 x 16)
208 g 233 g
26 g ?
Stoichiometry indicates that 208 g BaCl2 gives 233 g BaSO4
