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Some Basic Concepts Of Chemistry

Question
CBSEENCH11005068

Balance the given skeletion equation KMnO subscript 4 space plus space straight H subscript 2 SO subscript 4 space plus space left parenthesis COOH right parenthesis subscript 2 space space rightwards arrow space space straight K subscript 2 SO subscript 4 plus MnSO subscript 4 plus straight H subscript 2 straight O plus CO subscript 2 by partial equation method.

Solution

 It involves the following steps:
(i) Reaction between KMnO4 and H2SO4 to liberate nascent oxygen.2 KMnO subscript 4 plus 3 straight H subscript 2 SO subscript 4 space rightwards arrow space space space straight K subscript 2 SO subscript 4 plus 2 MnSO subscript 4 space plus 3 straight H subscript 2 straight O space plus 5 straight O                      ...(1)
(ii) Oxalic acid is oxidised to CO2 and water by the nascent oxygen.
open parentheses COOH close parentheses subscript 2 plus straight O space rightwards arrow space 2 CO subscript 2 plus 2 straight H subscript 2 straight O                           ...(2)
Multiplying equation (2) by 5 and adding partial equations,
text 2KMnO end text subscript 4 plus 3 straight H subscript 2 SO subscript 4 space rightwards arrow space space straight K subscript 2 SO subscript 4 plus 2 MnSO subscript 4 plus 3 straight H subscript 2 straight O plus 5 straight O
open square brackets open parentheses COOH close parentheses subscript 2 plus straight O space rightwards arrow space space space 2 CO subscript 2 plus 2 straight H subscript 2 straight O close square brackets cross times 5
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2 KMnO subscript 4 plus 3 straight H subscript 2 SO subscript 4 plus 5 left parenthesis COOH right parenthesis subscript 2 space rightwards arrow space space space straight K subscript 2 SO subscript 4
space space space space space space space space space space space space space space space space space space space space space plus 2 MnSO subscript 4 plus 10 CO subscript 2 plus 8 straight H subscript 2 straight O