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Some Basic Concepts Of Chemistry

Question
CBSEENCH11005067

Balance the following equation by partial equation method:
Cu plus HNO subscript 3 space rightwards arrow space Cu left parenthesis NO subscript 3 right parenthesis subscript 2 plus NO subscript 2 plus straight H subscript 2 straight O


Solution
It involves the following steps:
(i) Nitric acid decomposes to liberate nascent oxygen.
2 HNO subscript 3 space rightwards arrow space 2 NO subscript 2 plus straight H subscript 2 straight O plus straight O               ...(1)
(ii) Nascent oxygen reacts with copper to form cupric oxide.
Cu plus straight O space rightwards arrow space CuO    ...(2)
(iii) Cupric oxide combines with nitric acid to form cupric nitrate.
CuO plus 2 HNO subscript 3 space rightwards arrow space Cu left parenthesis NO subscript 3 right parenthesis subscript 2 plus straight H subscript 2 straight O               ...(3)
Adding all the partial equation (1), (2) and (3), we get the balanced equation as
Cu plus 4 HNO subscript 3 space rightwards arrow space space Cu left parenthesis NO subscript 3 right parenthesis subscript 2 plus 2 NO subscript 2 plus 2 straight H subscript 2 straight O