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Some Basic Concepts Of Chemistry

Question
CBSEENCH11005045

A sample of hydrazine consists of 87·42% N and 12·58% H by mass. The molecular mass of hydrazine is 32·0 g mol–1. Calculate its molecular formula.

Solution
(i) To calculate the empirical formula

(ii) To calculate the molecular formula:
             Empirical formula mass left parenthesis NH subscript 2 right parenthesis space equals space 14 space plus 2 space cross times space 1 space equals space 16 space straight g space mol to the power of negative 1 end exponent
                     Molecular space mass space of space hydrazine space equals space 32 space straight g space mol to the power of negative 1 end exponent
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space straight n space equals space fraction numerator Molecular space mass space of space hydrazine over denominator Empirical space formual space mass end fraction space equals fraction numerator 32 space straight g space mol to the power of negative 1 end exponent over denominator 16 space straight g space mol to the power of negative 1 end exponent end fraction equals 2
therefore space space space Molecular space formula space of space hydrazine space equals space space left parenthesis Empirical space formula right parenthesis subscript straight n
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals left parenthesis NH subscript 2 right parenthesis subscript 2
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