2.38 g of uranium was heated strongly in a current of air. The resulting oxide weighed 2806 g. Determine the empirical formula of the oxide. (At. mass of U = 238, O = 16).

Solution

(i) To calculate the percentage of uranium and oxygen in the oxide:

2.806 space straight g space of space oxide space contains space uranium space equals space 2.38 space straight g therefore space space space space space space Percentage space of space uranium space equals space fraction numerator 2.38 over denominator 2.806 end fraction cross times 100 space equals space 84.82 Hence comma space the space percentage space of space oxygen space in space the space oxide space equals space 100.00 space minus 84.82 space equals space 15.18

(ii) To calculate the empirical formula of the oxide:

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