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Some Basic Concepts Of Chemistry

Question
CBSEENCH11004982
Wired Faculty App

If the speed of light is 3·0 × 108 ms–1, calculate the distance covered by light in 2.00 ns.

Solution

Distance covered  = Speed x Time
  equals space 3.0 space cross times space 10 to the power of 8 space ms to the power of negative 1 end exponent space cross times space 2.00 space ns equals 3.0 space cross times 10 to the power of 8 space ms to the power of negative 1 end exponent cross times 2.00 space ns space cross times space fraction numerator 10 to the power of negative 9 end exponent straight s over denominator 1 space ns end fraction equals space 6.00 space cross times space 10 to the power of negative 1 end exponent straight m space equals space 0.600 space straight m

Some More Questions From Some Basic Concepts of Chemistry Chapter

What is the number of significant figures in 9.984?

Express the Avogadro's number (6·023×1023) upto three significant figures.

What is the result of (5.472 - 1.12) to the appropriate number of signficant figures?

Express 0.0468 in scientific notation.

What does SI units stand for?

What is the relation between temperature in Kelvin (K) and temperature on centigrade scale?

The popular unit of pressure is atmosphere, how is it related to pascal?

What are SI units of the following:

(i) Density    
(ii) Molarity          
(iii) Energy    
(iv) Temperature ?

Out of 5.00 g and 5.0 g which one is more accurate and why?

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