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Some Basic Concepts Of Chemistry

Question
CBSEENCH11004968

Express the result of the following calculations to the appropriate number of siginficant figures:

fraction numerator 3.24 space cross times space 0.08666 over denominator 5.006 end fraction

Solution
fraction numerator 3.24 space cross times 0.08666 over denominator 5.006 end fraction space equals space 0.0560833 space left parenthesis Actual space result right parenthesis
As the number of significant-figures in the least precise factor is three (viz 3.24), therefore, the reported result after rounding off is 0·0561 (containing only three significant figures).