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Some Basic Concepts Of Chemistry

Question
CBSEENCH11004967

Compute the following keeping in view the proper number of significant figures:

fraction numerator 52.874 space cross times space 0.03482 over denominator 0.24 space cross times 8 end fraction

Solution
fraction numerator 52.874 space cross times space 0.03482 over denominator 0.24 space cross times 8 end fraction space equals space 0.958892 space left parenthesis Actual space result right parenthesis
Leaving the exact number 8, the least precise term has two significant figures. Therefore, the reported result after rounding off is 0·96 (containing only two significant figures).