How many litres of oxygen at S.T.P. will be required to burn completely 2.2g of propane?

Solution

stack straight C subscript 3 straight H subscript 8 with stack 1 space mole with left parenthesis 44 space straight g right parenthesis below below space plus space stack 5 straight O subscript 2 with stack 5 cross times 22.4 space straight L with at space STP below below space space space rightwards arrow space space space space 3 CO subscript 2 space plus space 4 straight H subscript 2 straight O

44 space straight g space propane space equals space 5 space cross times space 22.4 space straight L space straight O subscript 2 space at space STP

therefore space space space 2.2 space straight g space propane space equals space fraction numerator 5 space cross times space 22.4 over denominator 44 end fraction cross times space 2.2 space equals space 5.6 space 5.6 space Liter thin space straight O subscript 2 space at space straight S. straight T. straight P.

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